Is that formula proper isn't it 1/2[x1(y2-y3) x2(y3-y1) x3(y1-y2)] So I think solution may change . In this question they have taken formula as 1/2[x1(y2-y3) x2(y3-y1) x3(y1-y3)]
Displaying ads are our only source of revenue. To help Teachoo create more content, and view the ad-free version of Teachooo... please purchase Teachoo Black subscription.
Please login to view more pages. It's free :)
Teachoo gives you a better experience when you're logged in. Please login :)
Solve all your doubts with Teachoo Black!
Teachoo answers all your questions if you are a Black user!