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two right angle triangles abc and dbc are on the same hypotenues bc and on the same side of bc if ac and bd intersect at p prove that ap x pc =bp x dp

two right angle triangles abc and dbc are on the same hypotenues bc and on the same side of bc if ac and bd intersect at p prove that ap x pc =bp x dp

two right angle triangles abc and dbc are on the same hypotenues bc and on the same side of bc if ac and bd intersect at p prove that ap x pc =bp x dp