Question
In triangles AOB and DOC
AB = CD. (Given)
OB = OD. (Given)
(Angle)AOB = (Angle)DOC. (Vertically opposite angle)
∆AOB =~∆DOC
(ar)AOB =(ar)DOC. (SAS rule)
AB = CD. (Given)
OB = OD. (Given)
(Angle)AOB = (Angle)DOC. (Vertically opposite angle)
∆AOB =~∆DOC
(ar)AOB =(ar)DOC. (SAS rule)
I was studying in class 10 I have a question in chapter 12 ex 12.2 q. 7 my teachers was sayinge in solution we have to use the Pythagoras theorem is it right or not
All scholl mathematics includind 10+1 , 10+2 ,iit jee mains advanced
All scholl mathematics includind 10+1 , 10+2 ,iit jee mains advanced
Age (in years) 5-15 15-25 25-35 35-45 45-55 55-65
No. of participants 6 11 21 23 14 5
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