Question
find the equation of the line passing through the points (2,5)and (3,6)
Cosec^2=1 cot^2A (how did u wrote this like this👇👇👇
Cosec^2A=1 (1/√sec^2A-1)^2
In exercise 8.4 2 nd main
Explain it plz
Cosec^2A=1 (1/√sec^2A-1)^2
In exercise 8.4 2 nd main
Explain it plz
in the given figure de parallel ac and df parallel ae prove that bf/fe=be/ec
in the given figure de parallel ac and df parallel ae prove that bf/fe=be/ec
Let ABC be a right triangle in which AB =6cm , BC=8cm and B=90°.BD is the perpendicular form B on AC. the circle though B,C,D is drawn . Construct the tangent form A to this circle
find a g.p for which sum of the first two terms is -4and the 5th term is 4 times the third term
The equation of the line in vector form passing through the point (-1,3,5) and parallel to line (x-3)/2=(y-4)/3=,z=2 is