two right angle triangles abc and dbc are on the same hypotenues bc and on the same side of bc if ac and bd intersect at p prove that ap x pc =bp x dp
two right angle triangles abc and dbc are on the same hypotenues bc and on the same side of bc if ac and bd intersect at p prove that ap x pc =bp x dp
two right angle triangles abc and dbc are on the same hypotenues bc and on the same side of bc if ac and bd intersect at p prove that ap x pc =bp x dp