Cos square(x) cos square(x+π/3)+cos square (x-π/3)=3/
A = R – {2/3} defined as f(x) = 4x+3/6x-4 is one-one and onto. Hence find f-1
(4x^2-9y^2)^3+(9y^2-16z^2)^3+(16z^2-4x^2)*2/(2x-3y)^3+(3y-4z)^3+(4z-2x)^3
State that R on the set A={1,2,3} Defined by R={(1,1)(2,2)(3,3)is an Equivalence relation