Question 37 (iii) (Choice 2) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at April 16, 2024 by Teachoo

In what direction is the ring getting pulled?

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Transcript

To find direction, we need to find Resultant force Now, Resultant force exerted by teams (𝑭 ⃗) = 𝑎 ⃗+𝑏 ⃗+𝑐 ⃗ = −𝒊 ˆ + 𝒋 ˆ This is in direction of 𝒃 ⃗ . Finding angle of vector 𝒃 ⃗ with respect to x-axis Now, Resultant force (𝑭 ⃗) = −𝒊 ˆ + 𝒋 ˆ And, Vector of x-axis = 𝑥 ⃗ = 𝒊 ˆ Now, 𝐹 ⃗.𝑥 ⃗=|𝐹 ⃗ ||𝑥 ⃗ | cos⁡〖𝜃 〗 (−𝒊 ˆ + 𝒋 ˆ) . 𝒊 ˆ = √𝟐 × 1 × cos θ −1 = √2 × cos θ (−1)/√2 = cos θ cos θ = (−𝟏)/√𝟐 Since cos is negative ∴ Angle is in second quadrant And, cos 𝝅/𝟒 = 𝟏/√𝟐 Therefore, Required angle = 𝜋 − 𝜋/4 = 𝟑𝝅/𝟒

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