If a =4i ˆ+6j ˆ and b =3j ˆ+4k ˆ, then the vector form of the component of a  along b  is

(a) 18/5 (3i ˆ+4k ˆ )                            (b) 18/25 (3j ˆ+4k ˆ )

(c) 18/5 (3i ˆ+4k ˆ )                            (d) 18/25(4i ˆ+6j ˆ)

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Transcript

Now, Vector component of 𝑎 ⃗ along 𝑏 ⃗ = Projection × Unit vector of 𝒃 ⃗ = 𝟏/("|" 𝒃 ⃗"|" ) (𝑎 ⃗. 𝑏 ⃗) × 𝑏 ⃗/(|𝑏 ⃗|) = ((𝑎 ⃗". " 𝑏 ⃗)/〖\ |𝑏 ⃗|〗^2 ) 𝑏 ⃗ ) Now, 𝒂 ⃗ = 4𝑖 ˆ+6𝑗 ˆ = 𝟒𝒊 ˆ+𝟔𝒋 ˆ + 0 𝒌 ˆ 𝒃 ⃗ = 3𝑗 ˆ+4𝑘 ˆ = 0𝒊 ˆ + 𝟑𝒋 ˆ+𝟒𝒌 ˆ Finding 𝒂 ⃗. 𝒃 ⃗ (𝒂 ⃗. 𝒃 ⃗) = (4 × 0) + (6 × 3) + (0 × 4) = 0 + 18 + 0 = 18 Magnitude of 𝑏 ⃗ = √(02+32+42) |𝒃 ⃗ | = √(0+9+16) = √25 = 5 Now, Vector component of 𝑎 ⃗ along 𝑏 ⃗ = ((𝑎 ⃗". " 𝑏 ⃗)/〖\ |𝑏 ⃗|〗^𝟐 ) 𝑏 ⃗ = 18/〖\ 5〗^𝟐 (3𝑗 ˆ+4𝑘 ˆ) = 𝟏𝟖/𝟐𝟓 (𝟑𝒋 ˆ+𝟒𝒌 ˆ ) So, the correct answer is (b)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.