![Ex 4.2, 15 - Chapter 4 Class 12 Determinants - Part 2](https://d1avenlh0i1xmr.cloudfront.net/4a397992-1878-43ae-8d4b-8ef738e083bf/slide64.jpg)
Properties of Determinant
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 6 Important Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 8 (i) Important Deleted for CBSE Board 2024 Exams
Question 8 (ii) Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 10 (i) Deleted for CBSE Board 2024 Exams
Question 10 (ii) Important Deleted for CBSE Board 2024 Exams
Question 11 (i) Deleted for CBSE Board 2024 Exams
Question 11 (ii) Important Deleted for CBSE Board 2024 Exams
Question 12 Important Deleted for CBSE Board 2024 Exams
Question 13 Important Deleted for CBSE Board 2024 Exams
Question 14 Important Deleted for CBSE Board 2024 Exams
Question 15 (MCQ) Important Deleted for CBSE Board 2024 Exams You are here
Question 16 (MCQ) Deleted for CBSE Board 2024 Exams
Properties of Determinant
Last updated at April 16, 2024 by Teachoo
Question 15 Choose the correct answer. Let A be a square matrix of order 3 × 3, then |"kA" | is equal to A. "k" |"A" | B. "k" 2|"A" | C. "k" 3|"A" | D. 3"k" |"A" | Let A = [■8(𝑎1&𝑏1&𝑐1@𝑎2&𝑏2&𝑐2@𝑎3&𝑏3&𝑐3)]_(3 × 3) We need to find |kA| kA = k [■8(𝑎1&𝑏1&𝑐1@𝑎2&𝑏2&𝑐2@𝑎3&𝑏3&𝑐3)] = [■8(𝒌𝑎1&𝒌𝑏1&𝒌𝑐1@𝒌𝑎2&𝒌𝑏2&𝒌𝑐2@𝒌𝑎3&𝒌𝑏3&𝒌𝑐3)] If a matrix is multiplied by a constant, then constant is multiplied to all elements of matrix |"kA" | = |■8(𝑘𝑎1&𝑘𝑏1&𝑘𝑐1@𝑘𝑎2&𝑘𝑏2&𝑘𝑐2@𝑘𝑎3&𝑘𝑏3&𝑘𝑐3)| Taking out k common from R1 R2 & R3 = k. k. k |■8(a1&b1&c1@a2&b2&c2@a3&b3&c3)| = k3 |■8(a1&b1&c1@a2&b2&c2@a3&b3&c3)| = k3 |A| Thus, Correct answer is C Property: If each element of row of determinant is multiplied by a constant k , then its value get multiplied by k