Ex 3.2, 9 - Chapter 3 Class 11 Trigonometric Functions

Last updated at April 16, 2024 by

Slide26.JPG

Slide27.JPG

Transcript

Ex 3.2,9 Find the value of the trigonometric function sin (–11"Ο€" /3) sin ((βˆ’πŸπŸ 𝝅)/πŸ‘) = –sin ((11 πœ‹)/3) = –sin ("3 " 𝟐/πŸ‘ " Ο€" ) = –sin ("4Ο€ – " 𝟏/πŸ‘ " Ο€" ) = –sin ((βˆ’πŸ)/πŸ‘ " Ο€" ) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 – 1/3 We take 4 – 𝟏/πŸ‘ as it is even = – ("–sin " (1/3 " Ο€" )) = sin (𝟏/πŸ‘ " Ο€" ) = sin 60Β° = βˆšπŸ‘/𝟐

Go Ad-free
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.