Bag/ Box / Piggy bank
Bag/ Box / Piggy bank
Last updated at April 16, 2024 by Teachoo
Ex 14.1, 10 A piggy bank contains hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins and ten Rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin will be a 50 p coin? Total number of coins in a piggy bank = 100 + 50 + 20 + 10 = 180 Number of 50 p coins = 100 Probability of getting a 50 p coin = (ππ’ππππ ππ πππππ ππ 50π)/(πππ‘ππ ππ’ππππ ππ πππππ ) = 100/180 = π/π Ex 14.1, 10 A piggy bank contains hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins and ten Rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (ii) will not be a βΉ 5 coin? Total number of coins in a piggy bank = 180 Number of βΉ 5 coins = 10 P(not getting a βΉ 5 coin) = 1 β P(getting a βΉ 5 coin) Now, P(getting a βΉ 5 coin) = (ππ’ππππ ππ πππππ ππ βΉ 5 )/(πππ‘ππ ππ’ππππ ππ πππππ ) = 10/180 = π/ππ Thus, P(not getting a βΉ 5 coin) = 1 β P(getting a βΉ 5 coin) = 1 β 1/18 = ππ/ππ