Ex 10.3, 4 - Find projection of i + 3j + 7k on 7i - j + 8k

Ex 10.3, 4 - Chapter 10 Class 12 Vector Algebra - Part 2

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Ex 10.3, 4 Find the projection of the vector š‘– Ģ‚ + 3š‘— Ģ‚ + 7š‘˜ Ģ‚ on the vector 7š‘– Ģ‚ - š‘— Ģ‚ + 8š‘˜ Ģ‚ . Projection of vector š’‚ āƒ— on š’ƒ āƒ— = šŸ/|š’ƒ āƒ— | (š’‚ āƒ—. š’ƒ āƒ—) Let š‘Ž āƒ— = 1š‘– Ģ‚ + 3š‘— Ģ‚ + 7š‘˜ Ģ‚ š‘ āƒ— = 7š‘– Ģ‚ – 1š‘— Ģ‚ + 8š‘˜ Ģ‚ (š’‚ āƒ— . š’ƒ āƒ—) = (1 Ɨ 7) + (3 Ɨ āˆ’1) + (7 Ɨ 8) = 7 + (āˆ’3) + 56 = 60 Magnitude of š‘ āƒ— = √(72+(āˆ’1)2+82) |š‘ āƒ— | = √(49+1+64) = āˆššŸšŸšŸ’ Projection of š‘Ž āƒ— on š‘ āƒ— = 1/|š‘ āƒ— | (š‘Ž āƒ—. š‘ āƒ—) = 1/√114 Ɨ 60 = 60/√114 Thus projection of š‘Ž āƒ— on š‘ āƒ— = šŸ”šŸŽ/āˆššŸšŸšŸ’

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