Ex 3.2, 10 - Chapter 3 Class 12 Matrices

Last updated at July 15, 2026 by

  Ex 3.2, 10 - Solve for x, y, z, t, if 2 [x z y t] + 3 [1 -1 0 2] - Ex 3.2

part 2 - Ex 3.2, 10 - Ex 3.2 - Serial order wise - Chapter 3 Class 12 Matrices
part 3 - Ex 3.2, 10 - Ex 3.2 - Serial order wise - Chapter 3 Class 12 Matrices

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Transcript

Ex 3.2,10 Solve the equation for x, y, z and t, if 2[โ– 8(๐‘ฅ&๐‘ง@๐‘ฆ&๐‘ก)] + 3 [โ– 8(1&โˆ’1@0&2)] = 3 [โ– 8(3&5@4&6)] 2[โ– 8(๐‘ฅ&๐‘ง@๐‘ฆ&๐‘ก)] + 3 [โ– 8(1&โˆ’1@0&2)] = 3 [โ– 8(3&5@4&6)] [โ– 8(๐‘ฅร—2&๐‘งร—2@๐‘ฆร—2&๐‘กร—2)] + [โ– 8(1ร—3&โˆ’1ร—3@0ร—3&2ร—3)] = [โ– 8(3ร—3&5ร—3@4ร—3&6ร—3)] [โ– 8(2๐‘ฅ&2๐‘ง@2๐‘ฆ&2๐‘ก)] + [โ– 8(3&โˆ’3@0&6)] = [โ– 8(9&15@12&18)] [โ– 8(2๐‘ฅ+3&2๐‘งโˆ’3@2๐‘ฆ+0&2๐‘ก+6)] = [โ– 8(9&15@12&18)] [โ– 8(๐Ÿ๐’™+๐Ÿ‘&๐Ÿ๐’›โˆ’๐Ÿ‘@๐Ÿ๐’š&๐Ÿ๐’•+๐Ÿ”)] = [โ– 8(๐Ÿ—&๐Ÿ๐Ÿ“@๐Ÿ๐Ÿ&๐Ÿ๐Ÿ–)] Since matrices are equal. Corresponding elements are equal 2x + 3 = 9 2y = 12 2z โ€“ 3 = 15 2t + 6 = 18 Solving equation (1) 2x + 3 = 9 2x = 9 โ€“ 3 x = 6/2 x = 3 Solving equation (2) 2y = 12 y = 12/2 y = 6 Solving equation (3) 2z โ€“ 3 = 15 2z = 15 + 3 z = 18/2 z = 9 Solving equation (4) 2t + 6 = 18 2t = 18 โ€“ 6 t = 12/2 t = 6 Hence x = 3 , y = 6 , z = 9 & t = 6

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