Last updated at April 16, 2024 by Teachoo
Example 6 Savita and Hamida are friends. What is the probability that both will have different birthdays? (ignoring a leap year). P(both have different birthday) = P(both will not have same birthday) = 1 โ P(both will have same birthday) = 1 โ 1/365 = (365 โ 1)/365 = ๐๐๐/๐๐๐ Example 6 Savita and Hamida are friends. What is the probability that both will have (ii) same birthday? (ignoring a leap year). Number of days in an year = 365 Number of days when same birthday is possible = 1 P(both have same birthday) = (๐๐ข๐๐๐๐ ๐๐ ๐๐๐ฆ๐ ๐คโ๐๐๐ ๐กโ๐๐ฆ ๐๐๐ โ๐๐ฃ๐ ๐ ๐๐๐ ๐๐๐๐กโ๐๐๐ฆ ๐๐ ๐๐ ๐ฆ๐๐๐)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐๐ฆ๐ ๐๐ ๐๐ ๐ฆ๐๐๐) = ๐/๐๐๐