Last updated at April 16, 2024 by Teachoo
Example 3 Suppose we throw a die once. What is the probability of getting a number greater than 4 ? Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Total number of outcomes = 6 Numbers greater than 4 = 5 & 6 Number of outcomes where number is greater than 4 = 2 Probability of getting a number greater than 4 = (ππ’ππππ ππ ππ’π‘πππππ π€βπππ π‘βπππ ππ π ππ’ππππ πππππ‘ππ π‘βππ 4)/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = 2/6 = π/π Example 3 (Method 1) Suppose we throw a die once. (ii) What is the probability of getting a number less than or equal to 4? Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Total number of outcomes = 6 Numbers less than or equal to 4 = 1, 2, 3, & 4 Number of outcomes where number is less than or equal to 4 = 4 Probability of getting a number less than or equal to 4 = (ππ’ππππ ππ ππ’π‘πππππ π€βπππ π‘βπππ ππ π ππ’ππππ πππ π π‘βππ ππ πππ’ππ π‘π 4)/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = 4/6 = π/π Example 3 (Method 2) Suppose we throw a die once. (ii) What is the probability of getting a number less than or equal to 4 ? P(getting a number less than or equal to 4) = 1 β P(not getting a number less than or equal to 4) = 1 β P(getting a number greater than 4) = 1 β 1/3 = π/π