Slide59.JPG

Slide60.JPG

Go Ad-free

Transcript

Ex 14.1, 19 A child has a die whose six faces shows the letters as given below: The die is thrown once. What is the probability of getting A? Total number of faces on the die = 6 Number of faces having A on it = 2 P (getting A) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 ℎ𝑎𝑣𝑖𝑛𝑔 𝐴)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 𝑜𝑛 𝑑𝑖𝑒) = 2/6 = 𝟏/𝟑 Ex 14.1, 19 A child has a die whose six faces shows the letters as given below: The die is thrown once. What is the probability of getting (ii) D? Total number of faces on the die = 6 Number of faces having D on it = 1 P (getting D) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 ℎ𝑎𝑣𝑖𝑛𝑔 𝐷)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 𝑜𝑛 𝑑𝑖𝑒) = 𝟏/𝟔

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo