Given C is 10℅ less than A, so
C=x-(10/100)x
=9/10x
Given C is 20℅ more than B, so
C=B (20/100)B
9/10x=(12/10)B .............{C=9/10x}
B=(9/10x)/(12/10)
= (9/10x)×(10/12)
=3/4x
Now, A=x and B=3/4x
We have to find difference between A and B.
i.e. A–B
= x–3/4x
=1/4x
=25℅
Written on Jan. 7, 2017, 6:47 p.m.