• Answer of this question

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    crafts with Khwaish chawla's image
    crafts with Khwaish chawla

    Steps of Construction:
    Step 1: A ray QX is drawn and cut off a line segment QR = 6 cm from it.
    Step 2:. A ray QY is constructed making an angle of 60º with QR and YQ is produced to form a line YQY'
    Step 3: Cut off  a line segment QS = 2cm  from QY'. RS is joined.
    Step 5: Draw perpendicular bisector  of RS intersecting QY at a point  P. PR is joined.
    Thus, ΔPQR is the required triangle


    Written on Feb. 20, 2019, 7:41 p.m.