Let the 3 terms in AP be a-d,a and a+d then a-d+a+a+d=21 3a=21, a=7 now, (a-d)(a+d)=a+6 ie, (7-d)(7+d)=13 d^2=36 d=-6 or 6

Answer of this question

The sum of three consecutive terms of an AP is 21 and the product of t

Andleeb Mahtab

Let the 3 terms in AP be a-d,a and a+d

then a-d+a+a+d=21

3a=21, a=7

now, (a-d)(a+d)=a+6

ie, (7-d)(7+d)=13

d^2=36

d=-6 or 6

Written on Feb. 9, 2019, 11:23 a.m.

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Class 6