We know that, A+B+C=180° =B+C=180°-C =(B+C/2)=180°/2-A/2 =sin(B+C/2)=sin(90°-A/2) =SIN(B+C/2)=cosA/2. prove

Answer of this question
1. Prove that, sinA{B+C/2}=cosA/2

HS Hafizur Rahman

We know that,

A+B+C=180°

=B+C=180°-C

=(B+C/2)=180°/2-A/2

=sin(B+C/2)=sin(90°-A/2)

=SIN(B+C/2)=cosA/2. prove

Written on Jan. 27, 2019, 3:48 p.m.

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