In ∆SPQ and In ∆RQO angle spq = rqo Sp=Rq(becoz || ss of parallelogram are=) s as angle 1 ,r angle as 2 (1=2) So triangle congruent by asa 1 2 (crsp angles) 2angle 1 : 180 Angle 1 =180/2 1=90
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