• Answer of this question

    Sin3x cos4x
    Ramesh Kumar's image
    Ramesh Kumar
    = 1/2[sin(3x 4x) sin(3x-4x)]
    =1/2[sin7x sin(-x)]
    =1/2[sin7x sinx]
    =1/2(sin7x-sinx)dx
    =1/2[-cos7x/7 -(-cos)]
    I=1/2[cos-1/7cos7 c

    Written on Feb. 13, 2018, 7:03 p.m.

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