Answers!
It will have two positive and one negative root.
Putting 1 in the equation we get (1³) - 2 - 1 2=0
We get (x-1) is a root of the above equation.
Now, x²(x-1) -x(x-1) -2(x-1) is the condensed form of cubic equation.
Now, cubic equation can be written as (x-1)(x²-x-2). Solving for quadratic equation we get
(x-1)(x-2)(x 1)
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Answer the question...
It will have two positive and one negative root.
Putting 1 in the equation we get (1³) - 2 - 1 2=0
We get (x-1) is a root of the above equation.
Now, x²(x-1) -x(x-1) -2(x-1) is the condensed form of cubic equation.
Now, cubic equation can be written as (x-1)(x²-x-2). Solving for quadratic equation we get
(x-1)(x-2)(x 1)
Putting 1 in the equation we get (1³) - 2 - 1 2=0
We get (x-1) is a root of the above equation.
Now, x²(x-1) -x(x-1) -2(x-1) is the condensed form of cubic equation.
Now, cubic equation can be written as (x-1)(x²-x-2). Solving for quadratic equation we get
(x-1)(x-2)(x 1)
Comment