Let’s look at some identities of determinant
-
Determinant of Identity matrix = 1
det (I) = 1
Where I is identity matrix of any order (1 × 1, 2 × 2, 3 × 3, … n × n)
-
det (A
T
) = det A
|A T | = |A|
-
|AB| = |A| |B|
-
|A
−1
| = 1/(|A|)
Proof :
AA −1 = I
|AA −1 | = |I|
|A| |A −1 | = −1
|A −1 |= 1/ |A|
-
|kA| = k n |A|
where n is order of matrix
-
Similarly,
|−A| = |−1 × A|
= (−1) n × |A| -
(adj A) A = A (adj) = |A| I
-
Deteminant of adj A
We know that
A (adj A) = |A|I
Taking determinant both sides
|A (adj A) | = ||A|I |
We know that
|kA| = k n |A|
| A || adj A | = | A | 𝑛 |I|
| A || adj A | = | A | 𝑛 × 1
| adj A | = |𝐴| 𝑛 / |𝐴|
|adj A | = | A | 𝑛−1
| adj A | = | A | n-1
where n is the order of determinant