Ex 12.2, 2 (iv) - Chapter 12 Class 8 Factorisation
Last updated at April 16, 2024 by Teachoo
Factorisation using identities
Factorisation using identities
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Transcript
Ex 12.2, 2 Factorise. (iv) 16𝑥^5 – 144𝑥^316𝑥^5 – 144𝑥^3 = 〖16𝑥〗^2 𝑥^3−144𝑥^3 Taking 𝑥^3 common, = 𝑥^3 (16𝑥^2−144) = 𝒙^𝟑 ((𝟒𝒙)^𝟐−(𝟏𝟐)^𝟐 ) Using 𝒂^𝟐− 𝒃^𝟐 = (a + b) (a − b) Here a = 4x and b = 12 = 𝑥^3 (4𝑥+12) (4𝑥−12) = 𝑥^3 (4𝑥+12) (4𝑥−12) Both have 4 as common factor = 𝑥^3 × 4 (𝑥 + 3) × 4 (𝑥 − 3) = 𝑥^3 × 4 × 4 (𝑥 + 3) (𝑥 − 3) = 16𝒙^𝟑 (𝒙 + 3) (𝒙 − 3)
