Ex 12.2, 2 (ii) - Chapter 12 Class 8 Factorisation

Last updated at April 16, 2024 by

Slide10.JPG

Go Ad-free

Transcript

Ex 12.2, 2 Factorise. (ii) 63𝑎^2 – 112𝑏^263𝑎^2 – 112𝑏^2 = (7 × 9)𝑎^2− (7 × 16)𝑏^2 Taking 7 common, = 7 (9𝑎^2−16b^2) = 7 ((𝟑𝒂^𝟐 )−(𝟒𝒃)^𝟐 ) Using 𝒙^𝟐−𝒚^𝟐=(𝑥+𝑦)(𝑥−𝑦) Here 𝑥=3𝑎 and 𝑦=4𝑏 = 7 (𝟑𝒂+𝟒𝒃) (𝟑𝒂−𝟒𝒃)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo