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Ex 12.1, 1 Find the common factors of the given terms. (vi) 〖16𝑥〗^3,−〖4𝑥〗^2, 32𝑥16𝒙^𝟑 = 16 × 𝑥^3 = 2 × 2 × 2 × 2 × 𝑥^3 = 2 × 2 × 2 × 2 × 𝒙 × 𝒙 × 𝒙 −4𝒙^𝟐 = −4 × 𝑥^2 = −1 × 4 × 𝑥^2 = −1 × 2 × 2 × 𝑥^2 = −1 × 2 × 2 × 𝒙 × 𝒙 32𝒙 = 32 × 𝑥 = 2 × 2 × 2 × 2 × 2 × 𝒙 So, 16𝒙^𝟑 = 2 × 2 × 2 × 2 × 𝑥 × 𝑥 × 𝑥 −4𝒙^𝟐 = −1 × 2 × 2 × 𝑥 × 𝑥 32𝒙 = 2 × 2 × 2 × 2 × 2 × 𝑥 So, Common factor = 2 × 2 × 𝑥 = 4 × 𝑥 = 4𝒙

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo