Multiplying 2 term with 2 terms
(3a + 4b) × (2a + 3b)
= 3a × (2a + 3b) + 4b × (2a + 3b)
= 3a × 2a + 3a × 3b + 4b × 2a + 4b × 3b
= 6a 2 + 9ab + 8ba + 12b 2
Since ab = ba
= 6a 2 + 9ab + 8ab + 12b 2
= 6a 2 + ab (9 + 8) + 12b 2
= 6a 2 + 17 ab + 12b 2
(x + 2) × (x + 4b)
= x × (x + 4) + 2 × (x + 4)
= x × x + 4 × x + 2 × x + 2 × 4
= x 2 + 4x + 2x + 8
= x 2 + x (4 + 2) + 8
= x 2 + 6x + 8