Algebra Identities - Identity IV
Algebra Identities - Identity IV
Last updated at Dec. 16, 2024 by Teachoo
Question 8 Using (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 , find (i) 103 × 104 103 × 104 = (100+3) ×(100+4) (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 Putting 𝑥 = 100 , 𝑎 = 3 & 𝑏 = 4 (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 Putting 𝑥 = 100 , 𝑎 = 3 & 𝑏 = 4