Algebra Identities - Identity IV
Algebra Identities - Identity IV
Last updated at Dec. 16, 2024 by Teachoo
Question 6 Using identities, evaluate. (i) 〖71〗^2 〖71〗^2 =(70+1)^2 (𝑎+𝑏)^2=𝑎^2+𝑏^2+2𝑎𝑏 Putting 𝑎 = 70 & 𝑏 = 1 = (70)^2+(1)^2+2(70)(1) = 4900+1+140 = 𝟓𝟎𝟒𝟏