Multiplying numbers with same base

a m × a n = a m + n

 

Let’s take some examples & check

 

2 5 × 2 3   = (2 × 2 × 2 × 2 × 2) × (2 × 2 × 2)

   = 2 8

 

∴ 2 5 × 2 3 = 2 5 + 3 = 2 8

 

Similarly,

  (−3) 4 × (−3) 2

  = (−3 × −3 × −3 × −3) × (−3 × −3)

  = −3 × −3 × −3 × −3 × −3 × −3

  = (−3) 6

 

∴ (−3) 4 (−3) 2 = (−3) 4 + 2 = (−3) 6

And for,

  5 6 × 5 3 = (5 × 5 × 5 × 5 × 5 × 5) × (5 × 5 × 5)

   = 5 × 5 × 5 × 5 × 5 × 5 × 5 × 5 × 5

   = 5 9

∴ 5 6 × 5 3 = 5 6 + 3 = 5 9

 

Dividing Numbers with same base

  a m /a n  = a m - n

  2 5 /2 3  = (2 × 2 × 2 × 2 × 2)/(2 × 2 × 2)

  = 2 × 2

            = 2 2

∴ 2 5 /2 3 = 2 5 - 3 = 2 2

 

Similarly,

  -3 4 /-3 2  = (-3 × -3 × -3 × -3)/(-3 × -3)

= -3 × -3

= (-3) 2

∴ (-3) 4 /(-3) 2  = (-3) 4 - 2 = (-3) 2

 

And for,

  5 6 /5 3  = (5 × 5 × 5 × 5 × 5 × 5)/(5 × 5 × 5)

 = 5 × 5 × 5

 = 5 3

   ∴ 5 6 /5 3  = 5 6 − 3   = 5 3

Power of a Power

 

Thus we can write

  (a m ) n = a m × n

 

Suppose we have

  (2 3 )  = 2 3 × 2       (As a m × a n = a m + n )

 = 2 6

So, (2 3 ) 2   = 2 3 × 2 = 2 6

 

Similarly,

  (3 2 ) 4   = 3 2 × 4

  = 3 8

 

  (7 4 ) 5   = 7 4 × 5

= 7 20

 

  (8 9 ) 3   = 8 9 × 3

= 8 27

 

Multiplying number with same power

We note that

  a m × b m = (a × b) m

 

Suppose we have

  2 2 × 3 2   = (2 × 2) × (3 × 3)

     = (2 × 3) × (2 × 3)

     = 6 × 6

     = 6 2

 

Thus,

  2 2 × 3 2 = (2 × 3) 2

    = 6 2

 

Similarly,

  5 3 × 7 3

= (5 × 5 × 5) × (7 × 7 × 7)

= (5 × 7) × (5 × 7) × (5 × 7)

= 35 × 35 × 35

= 35 3

 

∴ 5 3 × 7 3   = (5 × 7) 3

      = 35 3

 

Dividing number with same power

We note that

  a m /b m = (a/b) m

 

Suppose we have,

  2 2 /3 2  = (2 × 2)/(3 × 3)

 = 2/3 × 2/3

 = (2/3) 2

 

∴ 2 2 /3 2  = (2/3) 2

 

Similarly,

  5 3 /7 3   =  (5 × 5 × 5)/(7 × 7 × 7)

   = (5/7)×(5/7)×(5/7)

   = (5/7) 3

∴ 5 3 /7 3  = (5/7) 3

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo