Example 12 (i) - Chapter 11 Class 7 Exponents and Powers

Last updated at Dec. 16, 2024 by

Example 12 - Simplify (i) 12^4 x 9^3 x 4 / 6^3 x 8^2 x 27 (ii) 2^3

Example 12 - Chapter 13 Class 7 Exponents and Powers - Part 2

 

 

Go Ad-free

Transcript

Example 12 Simplify and write the answer in the exponential form (i) (〖12〗^4 × 〖 9〗^3 × 4)/(6^3 ×〖 8〗^2 × 27) (〖12〗^4 × 9^3 × 4)/(6^3 × 8^2 × 27) = ((2 × 2 × 3)^4 × (3 × 3)^3 × (2 × 2))/((2 × 3)^3 × 〖(2 × 2 × 2)〗^2 × (3 × 3 × 3)) = ((2^2 × 3)^4 × (3^2 )^3 × (2^2 ))/((2 × 3)^3 × 〖(2^3)〗^2 × (3^3)) = ((2^2 )^4 × (3)^4 × (3^2 )^3 × (2^2))/(2^3 × 3^3 × (2^3 )^2×〖 3〗^3 ) = (2^(2 × 4) × 3^4 × 3^(2 × 3) ×〖 2〗^2)/(2^3 × 3^3 × 2^(3 × 2) × 3^3 ) [(a × b)m = am × bm] [(am)n = am × n] = (2^8 × 3^4 × 3^6 ×〖 2〗^2)/(2^3 × 3^3 × 2^6 × 3^3 ) = ((2^8 ×〖 2〗^2 ) × (3^4 × 3^6))/((2^3 × 2^6 ) × (3^3 × 3^3)) = (2^(8 + 2) × 3^(4 + 6))/(2^(3 + 6) ×〖 3〗^(3 + 3) ) = 2^10/2^9 × 3^10/3^6 = 210 − 9 × 310 − 6 = 21 × 34 = 2 × 81 = 162 (Using am × an = am + n) (Using 𝑎^𝑚/𝑎^𝑛 = am − n)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo