Ex 11.1, 4 - A flooring tile has the shape of a parallelogram whose

Ex 11.1, 4 - Chapter 11 Class 8 Mensuration - Part 2
Ex 11.1, 4 - Chapter 11 Class 8 Mensuration - Part 3

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Question 4 A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 𝑚^2? (If required you can split the tiles in whatever way you want to fill up the corners). Given, Tile is in shape of parallelogram And, Base = 24 cm Height = 10 cm Now, Number of tiles required = (𝐴𝑟𝑒𝑎 𝑜𝑓 𝑓𝑙𝑜𝑜𝑜𝑟)/(𝐴𝑟𝑒𝑎 𝑜𝑓 𝑜𝑛𝑒 𝑡𝑖𝑙𝑒) Given, Area of floor = 1080 m2 = 1080 × (100)2 cm2 = 1080 × 100 × 100 cm2 = 1080 × 10000 cm2 Now, finding area of tile Area of tile = Area of parallelogram = Base × Height = 24 × 10 = 240 cm2 Now, Number of tiles required = (𝐴𝑟𝑒𝑎 𝑜𝑓 𝑓𝑙𝑜𝑜𝑜𝑟)/(𝐴𝑟𝑒𝑎 𝑜𝑓 𝑜𝑛𝑒 𝑡𝑖𝑙𝑒) = (1080 × 10000 )/240 = (1080 × 1000)/24 = (540 × 1000)/12 = (90 × 1000)/2 = 45 × 1000 = 45000 ∴ 45000 tiles are required to cover the floor.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo