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Example 11 - Chapter 9 Class 7 Perimeter and Area
Last updated at Dec. 16, 2024 by Teachoo
Perimeter of a combination of shapes
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
- Circumference of circle
-
Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Example 11 Sudhanshu divides a circular disc of radius 7 cm in two equal parts. What is the perimeter of each semicircular shape disc? (Use π = 22/7)Now, Perimeter of semicircle = Length of semicircle part + Length of AB Length of semicircle part Radius = r = 7 cm Length of semicircle part = 1/2 × Circumference of circle = 𝟏/𝟐 × 2𝜋r = 𝜋 r = 22/7 × 7 = 22 cm Length of AB AB = 2 × Radius = 2 × 7 = 14 cm Thus, Perimeter of semicircle = Length of semicircle part + Length of AB = 22 + 14 = 36 cm ∴ Perimeter is 36 cm
