You are here
Example 10 - Chapter 9 Class 7 Perimeter and Area
Last updated at April 16, 2024 by Teachoo
Perimeter of a combination of shapes
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
- Circumference of circle
-
Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Example 10 Find the perimeter of the given shape (Fig 11.32) (Take Ο = 22/7).Here, Perimeter of given shape = 4 Γ Length of curved blue line = 4 Γ Circumference of half circle Letβs find circumference of half circle Circumference of half circle Diameter = 14 cm Radius = r = π·πππππ‘ππ/2 = 14/2 = 7 cm Circumference of half circle = 1/2 Γ Circumference of circle = π/π Γ 2πr = πr = 22/7 Γ 7 = 22 cm Now, Perimeter of given shape = 4 Γ Circumference of half circle = 4 Γ 22 = 88 cm Hence, perimeter of given shape is 88 cm
