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Example 3 - Chapter 9 Class 7 Perimeter and Area
Last updated at April 16, 2024 by Teachoo
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
-
Area of parallelogram
- Area of triangle
- Circumference of circle
- Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Example 3 The two sides of the parallelogram ABCD are 6 cm and 4 cm. The height corresponding to the base CD is 3 cm. Find the (i) area of the parallelogram. (ii) the height corresponding to the base AD Finding area of parallelogram Using BE as height and CD as base Here, Base = CD = 6 cm Height = BE = 3 cm Area of parallelogram = Base × Height = CD × BE = 6 × 3 = 18 cm2 Now, we need to find height corresponding to base AD Let that height be BF Base = AD = 4 cm Height = BF = x Area of parallelogram = Base × Height 18 = AD × BF 18 = 4 × BF 4 × BF = 18 BF = 𝟏𝟖/𝟒 BF = 9/2 BF = 4.5 cm Area of parallelogram is 18 cm2 and height corresponding to base AD is 4.5 cm
