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Question 11 - Perimeter of a combination of shapes - Chapter 9 Class 7 Perimeter and Area
Last updated at Dec. 16, 2024 by Teachoo
Perimeter of a combination of shapes
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
- Circumference of circle
-
Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Question 11 Find the area of the quadrilateral ABCD. Here, AC = 22 cm, BM = 3 cm, DN = 3 cm, and BM ⊥ AC, DN ⊥ AC Area of quadrilateral ABCD = Area of ∆ABC + Area of ∆ADC Area of ∆ABC Base = b = AC = 22 cm Height = BM = 3 cm Area of ∆ABC = 1/2 × b × h = 1/2 × AC × BM = 1/2 × 22 × 3 = 1/1 × 11 × 3 = 33 cm2 Area of ∆ABC Base = b = AC = 22 cm Height = BM = 3 cm Area of ∆ABC = 1/2 × b × h Area of ∆ADC Base = b = AC = 22 cm Height = ND = 3 cm Area of ∆ABC = 1/2 × b × h = 1/2 × AC × BM = 1/2 × 22 × 3 = 1/1 × 11 × 3 = 33 cm2 = 1/2 × AC × ND = 1/2 × 22 × 3 = 1/1 × 11 × 3 = 33 cm2 Therefore, Area of quadrilateral ABCD = Area of ∆ABC + Area of ∆ADC = 33 + 33 = 66 cm2 ∴ Area of quadrilateral is 66 cm2
