Ex 11.4, 11 - Find the area of the quadrilateral ABCD. Here, AC = 22

Ex 11.4, 11 - Chapter 11 Class 7 Perimeter and Area - Part 2
Ex 11.4, 11 - Chapter 11 Class 7 Perimeter and Area - Part 3
Ex 11.4, 11 - Chapter 11 Class 7 Perimeter and Area - Part 4
Ex 11.4, 11 - Chapter 11 Class 7 Perimeter and Area - Part 5

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Question 11 Find the area of the quadrilateral ABCD. Here, AC = 22 cm, BM = 3 cm, DN = 3 cm, and BM ⊥ AC, DN ⊥ AC Area of quadrilateral ABCD = Area of ∆ABC + Area of ∆ADC Area of ∆ABC Base = b = AC = 22 cm Height = BM = 3 cm Area of ∆ABC = 1/2 × b × h = 1/2 × AC × BM = 1/2 × 22 × 3 = 1/1 × 11 × 3 = 33 cm2 Area of ∆ABC Base = b = AC = 22 cm Height = BM = 3 cm Area of ∆ABC = 1/2 × b × h Area of ∆ADC Base = b = AC = 22 cm Height = ND = 3 cm Area of ∆ABC = 1/2 × b × h = 1/2 × AC × BM = 1/2 × 22 × 3 = 1/1 × 11 × 3 = 33 cm2 = 1/2 × AC × ND = 1/2 × 22 × 3 = 1/1 × 11 × 3 = 33 cm2 Therefore, Area of quadrilateral ABCD = Area of ∆ABC + Area of ∆ADC = 33 + 33 = 66 cm2 ∴ Area of quadrilateral is 66 cm2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo