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Ex 9.2, 11 - Chapter 9 Class 7 Perimeter and Area
Last updated at April 16, 2024 by Teachoo
Area of combination of figures - two circles, circle and square
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
- Circumference of circle
- Perimeter of a combination of shapes
- Area of circle
-
Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Ex 9.2, 11 A circle of radius 2 cm is cut out from a square piece of an aluminum sheet of side 6 cm. What is the area of the left over aluminum sheet? (Take π = 3.14) Let ABCD be the square sheet of side 6 cm Remaining Area = Area of square sheet − Area of circular piece Area of square sheet Side of sheet = a = 6 cm Area of square sheet = a × a = 6 × 6 = 36 cm2 Area of circular Radius of circular = r = 2 cm Area of circular = 𝜋r2 = 3.14 × (2)2 = 314/100 × 4 = 1256/100 = 12.56 cm2 Now, Remaining Area = Area of square sheet − Area of circular piece = 36 − 12.56 = 36 − 1256/100 = (36 × 100 − 1256)/100 = (𝟑𝟔𝟎𝟎 − 𝟏𝟐𝟓𝟔)/𝟏𝟎𝟎 = 2344/100 = 23.44 cm2 ∴ 23.44 cm2 of area is left.
