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Ex 9.2, 6 - Chapter 9 Class 7 Perimeter and Area
Last updated at Dec. 16, 2024 by Teachoo
Perimeter of a combination of shapes
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
- Circumference of circle
-
Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Ex 9.2, 6 Saima wants to put a lace on the edge of a circular table cover of diameter 1.5 m. Find the length of the lace required and also find its cost if one meter of the lace costs Rs 15. (Take π = 3.14) Here, Length of lace = Circumference of table Given Diameter = 1.5 cm Radius = r = 𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟/2 = (𝟏.𝟓)/𝟐 = 15/(10 × 2) = 3/(2 × 2) = 𝟑/𝟒 m Circumference of table = 2𝜋r = 2 × 3.14 × 𝟑/𝟒 = 2 × 314/100 × 3/4 = 𝟑/𝟐 × 𝟑𝟏𝟒/𝟏𝟎𝟎 = 3 × 157/100 = 471/100 = 4.71 m So, length of lace required is 4.71 cm Now, we have to find cost Now, Cost of 1 m lace = Rs 15 Cost of 4.71 m lace = Rs 15 × 4.71 = Rs 15 × 𝟒𝟕𝟏/𝟏𝟎𝟎 = Rs 7065/100 = Rs 70.65 Cost of lace required is Rs 70.65 So, length of lace required is 4.71 cm Now, we have to find cost Now, Cost of 1 m lace = Rs 15 Cost of 4.71 m lace = Rs 15 × 4.71 = Rs 15 × 𝟒𝟕𝟏/𝟏𝟎𝟎 = Rs 7065/100 = Rs 70.65 Cost of lace required is Rs 70.65
