You are here
Ex 9.2, 4 - Chapter 9 Class 7 Perimeter and Area
Last updated at Dec. 16, 2024 by Teachoo
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
-
Circumference of circle
- Perimeter of a combination of shapes
- Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Ex 9.2, 4 A gardener wants to fence a circular garden of diameter 21m. Find the length of the rope he needs to purchase, if he makes 2 rounds of fence. Also find the cost of the rope, if it costs Rs 4 per meter. (𝑇𝑎𝑘𝑒 𝜋=22/7) Since the gardener makes two rounds of the fence Thus, Length of rope required = 2 × Circumference of circular garden Diameter = 21 m Radius = r = 𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟/2 = 𝟐𝟏/𝟐 m Circumference of circular garden = 2𝜋r = 2 × 𝟐𝟐/𝟕 × 𝟐𝟏/𝟐 = 22/7 × 21 = 22 × 3 = 66 m Now, Length of rope required = 2 × Circumference of circular garden = 2 × 66 = 132 m Now, we also need to find cost of rope, Given, Cost of 1 m rope = Rs 4 Cost of 132 m rope = Rs 4 × 132 = Rs 528 ∴ It would cost Rs 528 to fence the garden
