Let’s take a rectangle
We know that
In a rectangle, opposite sides are equal
AB = CD
& AD = BC
Let
AB = Length of rectangle = l
BC = Breadth of rectangle = b
So,
AB = CD = l
BC = AD = b
Now,
Perimeter of rectangle = Sum of all sides
= AB + BC + CD + DA
= l + b + l + b
= 2 l + 2b
= 2 ( l + b)
So,
Perimeter of rectangle = 2 ( l + b)
Let’s take some examples
Find perimeter of rectangle where length is 15cm & breadth is 9 cm
Given,
Length = l = 15 cm
Breadth = b = 9 cm
Perimeter of rectangle = 2 × (Length + Breadth)
= 2 × (15 + 9)
= 2 × 24
= 48 cm
So, perimeter of rectangle is 48 cm
Find perimeter of rectangle where length & breadth are 0.5 m & 0.2 m respectively.
Given,
Length = l = 0.5 cm
Breadth = b = 0.2 cm
Perimeter of rectangle = 2 × (Length + Breadth)
= 2 × (0.5 + 0.2)
= (2 × 0.7)
= 1.4 m
= 1.4 × 100 cm (1m = 100 cm)
= 140 cm