Question 5 - Examples - Chapter 7 Class 8 Comparing Quantities
Last updated at Dec. 16, 2024 by Teachoo
Examples
Example 1 (ii)
Example 1 (iii) Important
Example 2 Important
Example 3
Example 4
Example 5
Example 6 – GST (Page Number - 124)
Example 7 (Page no. 126) Important
Example 8
Example 9
Example 10 Important
Question 1
Question 2
Question 3 Important
Question 4 Important
Question 5 You are here
Question 6 Important
Last updated at Dec. 16, 2024 by Teachoo
Question 5 What amount is to be repaid on a loan of Rs 12000 for 1 1/2 years at 10% per annum compounded half yearly. Given Principal = Rs 12000 Here, rate is compounded half yearly. Rate of interest = R = 10/2 % = 5 % & Time = 1 1/2 years = 3/2 years = 3/2 × 2 half years = 3 Amount = P (1+𝑅/100)^𝑛 = 12000 (1+5/100)^3 = 12000 (1+1/20)^3 = 12000 ((20 + 1)/20)^3 = 12000 (21/20)^3 = 12000 × 21/20 × 21/20 × 21/20 = 12 × 21/2 × 21/2 × 21/2 = 3 × 21 × 21 × 21/2 = (63 × 441)/2 = 27783/2 = 13891.5 ∴ Amount = Rs 13,891.50