Question 17 (OR 1 st question)

Prove that cot ⁡θ - tan ⁡θ = (2 cos 2 ⁡θ  - 1) / (sin⁡ θ cos ⁡θ)

Prove that cot ⁡θ - tan ⁡θ = (2 cos^2 ⁡θ - 1) / (sin⁡ θ cos ⁡θ)

Question 17 (Or 1st) - CBSE Class 10 Sample Paper for 2019 Boards - Part 2

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Question 17 (OR 1st question) Prove that cot⁡𝜃−tan⁡𝜃 = (2 cos^2⁡𝜃 − 1)/(sin⁡𝜃 cos⁡𝜃 ) Solving LHS cot⁡𝜃−tan⁡𝜃 = cos⁡𝜃/sin⁡𝜃 −sin⁡𝜃/cos⁡𝜃 = (cos⁡𝜃 × cos⁡𝜃 − sin⁡𝜃 × sin⁡𝜃)/(sin⁡𝜃 cos⁡𝜃 ) = (cos^2⁡𝜃 − sin^2⁡𝜃)/(sin⁡𝜃 cos⁡𝜃 ) Now, sin2 θ + cos2 θ = 1 sin2 θ = 1 – cos2 θ = (cos^2⁡𝜃 − (1 − cos^2⁡𝜃))/(sin⁡𝜃 cos⁡𝜃 ) = (cos^2⁡𝜃 − 1 + cos^2⁡𝜃)/(sin⁡𝜃 cos⁡𝜃 ) = (2 cos^2⁡𝜃 − 1)/(sin⁡𝜃 cos⁡𝜃 ) = RHS Since LHS = RHS Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo