Example 5 - Practical Geometry

Last updated at Dec. 16, 2024 by

Example 5 - Draw a square of side 4.5 cm - Chapter 4 Class 8

Example 5 - Chapter 4 Class 8 Practical Geometry - Part 2
Example 5 - Chapter 4 Class 8 Practical Geometry - Part 3
Example 5 - Chapter 4 Class 8 Practical Geometry - Part 4
Example 5 - Chapter 4 Class 8 Practical Geometry - Part 5 Example 5 - Chapter 4 Class 8 Practical Geometry - Part 6

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Transcript

Example 5 Draw a square of side 4.5 cm. Let’s draw a rough figure In square, All sides are equal ∴ AB = BC = CD = AD = 4.5 cm And, All angles are 90° ∴ ∠ A = ∠ B = ∠ C = ∠ D = 90° So, we draw the square using 3 sides, and 2 angles method Steps of construction 1. Draw side AB of length 4.5 cm 2. Now, we draw 90° from point A Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Now, we draw 90° from point B Taking 4.5 cm as radius, and A as center. Draw an arc. Mark the point where arc and line intersect as D Taking 4.5 cm as radius, and B as center. Draw an arc. Mark the point where arc and line intersect as C Taking 4.5 cm as radius, and A as center. Draw an arc. Mark the point where arc and line intersect as D 5. Taking 4.5 cm as radius, and B as center. Draw an arc. Mark the point where arc and line intersect as C 5. Join CD Label the sides ∴ ABCD is the required square

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo