Example 2 - Practical Geometry

Last updated at April 16, 2024 by

Example 2 - Construct a quadrilateral ABCD, BC = 4.5 cm, AD = 5.5 cm

Example 2 - Chapter 4 Class 8 Practical Geometry - Part 2
Example 2 - Chapter 4 Class 8 Practical Geometry - Part 3
Example 2 - Chapter 4 Class 8 Practical Geometry - Part 4
Example 2 - Chapter 4 Class 8 Practical Geometry - Part 5 Example 2 - Chapter 4 Class 8 Practical Geometry - Part 6 Example 2 - Chapter 4 Class 8 Practical Geometry - Part 7 Example 2 - Chapter 4 Class 8 Practical Geometry - Part 8

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Transcript

Example 2 Construct a quadrilateral ABCD, given that BC = 4.5 cm, AD = 5.5 cm, CD = 5 cm the diagonal AC = 5.5 cm and diagonal BD = 7 cm. First we draw a rough sketch Let’s construct it Steps of construction 1. Draw diagonal AC of length 5.5 cm 2. First, we will mark point D Taking 5.5 cm as radius, and A as center, draw an arc on bottom of AC 3. Taking 5 cm as radius, and C as center, draw an arc on bottom of AC Mark point D as the point where two arcs intersect at bottom of AC Mark point D as the point where two arcs intersect at bottom of AC 6. Taking 7 cm as radius, and D as center, draw an arc on top of AC 7. Mark point B as the point where two arcs intersect at top of AC Join AB, BC, AD, CD, BD Label the sides

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo