Question 3 - Constructing Rectangle - Practical Geometry

Last updated at April 16, 2024 by

Ex 4.5, 3 - Draw a rectangle with adjacent sides of lengths 5 cm, 4

Ex 4.5, 3 - Chapter 4 Class 8 Practical Geometry - Part 2
Ex 4.5, 3 - Chapter 4 Class 8 Practical Geometry - Part 3
Ex 4.5, 3 - Chapter 4 Class 8 Practical Geometry - Part 4
Ex 4.5, 3 - Chapter 4 Class 8 Practical Geometry - Part 5 Ex 4.5, 3 - Chapter 4 Class 8 Practical Geometry - Part 6

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Question 3 A rectangle with adjacent sides of lengths 5 cm and 4 cm. Let’s draw a rough figure In rectangle, Opposite sides are equal ∴ AD = BC = 4 cm AB = DC = 5 cm And, All angles are 90° ∴ ∠ A = ∠ B = ∠ C = ∠ D = 90° So, we draw the rectangle using 3 sides, and 2 angles method Steps of construction 1. Draw side AB of length 5 cm 2. Now, we draw 90° from point A Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Now, we draw 90° from point B 4. Taking 4 cm as radius, and A as center. Draw an arc. Mark the point where arc and line intersect as D Taking 4 cm as radius, and B as center. Draw an arc. Mark the point where arc and line intersect as C 5. Join CD Label the sides ∴ ABCD is the required rectangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo