Ex 4.1, 1 (iv) - Construct Rhombus BEST, BE = 4.5 cm, ET = 6 cm

Ex 4.1, 1 (iv) - Chapter 4 Class 8 Practical Geometry - Part 2
Ex 4.1, 1 (iv) - Chapter 4 Class 8 Practical Geometry - Part 3
Ex 4.1, 1 (iv) - Chapter 4 Class 8 Practical Geometry - Part 4
Ex 4.1, 1 (iv) - Chapter 4 Class 8 Practical Geometry - Part 5 Ex 4.1, 1 (iv) - Chapter 4 Class 8 Practical Geometry - Part 6 Ex 4.1, 1 (iv) - Chapter 4 Class 8 Practical Geometry - Part 7

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Question 1 (iv) Construct the following quadrilaterals. Rhombus BEST BE = 4.5 cm ET = 6 cm In rhombus, All sides are equal ∴ BE = ES = ST = BT = 6 cm So, we have 4 sides and 1 diagonal Let’s construct it Steps of construction 1. Draw diagonal ET of length 6 cm 2. Taking 4.5 cm as radius, and E as center, draw an arc on top of ET 2. Taking 4.5 cm as radius, and E as center, draw an arc on top of ET 4. Taking 4.5 cm as radius, and E as center, draw an arc on bottom of ET 5. Taking 4.5 cm as radius, and T as center, draw an arc on bottom of ET 6. Let S be the point where arcs intersect on top of ET, and B be the point where arcs intersect below ET Join ES, ST, EB, BT Label the sides

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo