Example 1 - Practical Geometry

Last updated at April 16, 2024 by

Example 1 - Construct triangle ABC, given AB = 5 cm, BC = 6 cm, AC = 7

Example 1 - Chapter 10 Class 7 Practical Geometry - Part 2
Example 1 - Chapter 10 Class 7 Practical Geometry - Part 3
Example 1 - Chapter 10 Class 7 Practical Geometry - Part 4
Example 1 - Chapter 10 Class 7 Practical Geometry - Part 5

Go Ad-free

Transcript

Example 1 Construct a triangle ABC, given that AB = 5 cm, BC = 6 cm and AC = 7 cm. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment AB of length 5 cm 2. Taking 7 cm as radius, and A as center, draw an arc. 3. Taking 6 cm as radius, and B as center, draw another arc. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo