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Question 3 - Constructing a right triangle when hypotenuse and side is given (RHS) - Practical Geometry
Last updated at Dec. 16, 2024 by Teachoo
Constructing a right triangle when hypotenuse and side is given (RHS)
Practical Geometry
Concept wise
- Construction of line parallel to given line, through point not on line
- Constructing a triangle when 3 sides known (SSS)
- Constructing a triangle when 2 sides and angle between is known (SAS)
- Constructing a triangle when 2 angles and side between is known (ASA)
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Constructing a right triangle when hypotenuse and side is given (RHS)
Transcript
Question 3 Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm. Given Δ ABC where ∠ C = 90° AC = 6 cm Also, Δ ABC is isosceles Now, in a right angle triangle, Hypotenuse is the largest side. So, it can’t be equal to any other side ∴ BC = AC = 6 cm Let’s construct it Steps of construction 1. Draw a line segment AC of length 6 cm 2. Now, we draw 90° from point C Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Taking C as center, 6 cm as radius, we draw an arc Let the point where arc intersects the ray be point B 4. Join BA and label the sides Thus, Δ ABC is the required triangle
