Question 3 - Constructing a triangle when 2 sides and angle between is known (SAS) - Practical Geometry

Last updated at April 16, 2024 by

Ex 10.3, 3 - Construct ABC with BC = 7.5 cm, AC = 5 cm and C = 60

Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 3
Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 4
Ex 10.3, 3 - Chapter 10 Class 7 Practical Geometry - Part 5

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Transcript

Question 3 Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment CB of length 7.5 cm 2. Now, we draw 60° from point C 3. Taking C as center, 5 cm as radius, we draw an arc Let the point where arc intersects the ray be point A 4. Join AB and label the sides Thus, Δ ABC is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo